Question

\(\dfrac{\sqrt{x}+5}{2\left(\sqrt{x}-3\right)}< 0\)

Các bạn có thể giúp minh ko

Answer 1

\(\dfrac{\sqrt{x}+5}{2\left(\sqrt{x}-3\right)}< 0\left(ĐK:x\ge0\right)\)

<=> \(\dfrac{\sqrt{x}+5}{2\left(\sqrt{x}-3\right)}< \dfrac{0}{2\left(\sqrt{x}-3\right)}\)

<=> \(\sqrt{x}+5< 0\)

<=> \(\sqrt{x}< -5\)

<=> \(x< 25;\left(x\ge0\right)\)

<=> \(0\le x< 25\) 

Answer 2

\(ĐK:x\ge0;x\ne9\\ BPT\Leftrightarrow2\left(\sqrt{x}-3\right)< 0\left(\sqrt{x}+5\ge5>0\right)\\ \Leftrightarrow\sqrt{x}-3< 0\left(2>0\right)\\ \Leftrightarrow x< 9\\ \Leftrightarrow0\le x< 9\)