Question

\(\dfrac{\sqrt{x}-2}{\sqrt{x}-3}-\dfrac{3}{4}\)

Answer 1

\(\dfrac{\sqrt{x}-2}{\sqrt{x}-3}\)-\(\dfrac{3}{4}\)=\(\dfrac{\left(\sqrt{x}-2\right)\cdot4-3\cdot\left(\sqrt{x}-3\right)}{4\cdot\left(\sqrt{x}-3\right)}\)=\(\dfrac{4\sqrt{x}-8-3\sqrt{x}+9}{4\sqrt{x}-12}\)=\(\dfrac{\sqrt{x}+1}{4\sqrt{x}-12}\)