\(\dfrac{450}{x+30}-\dfrac{450}{x}=4\left(đk:x\ne0,x\ne-30\right)\)
\(\Leftrightarrow\dfrac{450x-450x-13500}{x\left(x+30\right)}=4\)
\(\Leftrightarrow\dfrac{-13500}{x\left(x+30\right)}=4\)
\(\Leftrightarrow4x^2+120x=-13500\)
\(\Leftrightarrow4\left(x+15\right)^2=-12600\)
\(\Leftrightarrow\left(x+15\right)^2=-3150\)(vô lý)
Vậy \(x\in\varnothing\)
\(\dfrac{450}{x+30}-\dfrac{450}{x}=4\)
<=> \(\dfrac{450x}{x\left(x+30\right)}-\dfrac{450\left(x+30\right)}{x\left(x+30\right)}=\dfrac{4x\left(x+30\right)}{x\left(x+30\right)}\)
<=> 450x - 450(x + 30) = 4x(x + 30)
<=> 450x - 450x - 480 = 4x2 + 120x
<=> 4x2 - 120x - 480 = 0
<=> x = 33, 57
Ta có: \(\dfrac{450}{x+30}-\dfrac{450}{x}=4\)
\(\Leftrightarrow4x\left(x+30\right)=450x-450\left(x+30\right)\)
\(\Leftrightarrow4x^2+120x+13500=0\)(vô lý)