\(\dfrac{4^{20}\cdot3^{35}}{2^{37}\cdot27^{12}}\\ =\dfrac{\left(2^2\right)^{20}\cdot3^{35}}{2^{37}\cdot\left(3^3\right)^{12}}\\ =\dfrac{2^{40}\cdot3^{35}}{2^{37}\cdot3^{36}}\\ =\dfrac{2^3}{3}\\ =\dfrac{8}{3}\)
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