Ta có: \(\left(\dfrac{3}{5}+0.415-\dfrac{3}{200}\right)\cdot2\dfrac{2}{3}\cdot0.25\)
\(=\left(\dfrac{120}{200}+\dfrac{83}{200}-\dfrac{3}{200}\right)\cdot\dfrac{8}{3}\cdot\dfrac{1}{4}\)
\(=\dfrac{8}{3}\cdot\dfrac{1}{4}=\dfrac{8}{12}=\dfrac{2}{3}\)
Ta có: \(\left(\dfrac{3}{5}+0.415-\dfrac{3}{200}\right)\cdot2\dfrac{2}{3}\cdot0.25\)
\(=\left(\dfrac{120}{200}+\dfrac{83}{200}-\dfrac{3}{200}\right)\cdot\dfrac{8}{3}\cdot\dfrac{1}{4}\)
\(=\dfrac{8}{3}\cdot\dfrac{1}{4}=\dfrac{8}{12}=\dfrac{2}{3}\)
Tìm x biết:
a) \(\left(3\dfrac{1}{2}+2x\right).3\dfrac{2}{3}=5\dfrac{1}{3}\)
b) \(\left(\dfrac{x}{7}+0,25\right)=\dfrac{-1}{28}\)
Tìm x
a,(4x-5).(\(\dfrac{5}{4}\)x-2)=0 b,(\(\dfrac{1}{12}\)+\(3\dfrac{1}{6}\)-30,75)x-8=(\(\dfrac{3}{5}\)+0,415+\(\dfrac{1}{200}\)):0,01
a) 0,25-\(\dfrac{2}{3}\)+1\(\dfrac{1}{4}\)
b) \(\dfrac{3^2}{2}\):\(\dfrac{1}{4}\)+\(\dfrac{3}{4}\).2010
c) {[(\(\dfrac{1}{25}\)-0,6)2:\(\dfrac{49}{125}\)].\(\dfrac{5}{6}\)}-[(\(\dfrac{-1}{3}\))+\(\dfrac{1}{2}\)]
d) (-\(\dfrac{1}{2}\)-\(\dfrac{1^{ }}{3}\))2:[(\(\dfrac{-5}{36}\))-(\(\dfrac{-5}{36}\))0]
Mn giúp mk nhé mk gấp quá tí đi học ai làm được mk thả tim và like nhé
Tìm x biết:
\(a,\dfrac{4}{5}+x=\dfrac{2}{3}\)
\(b,\dfrac{-5}{6}-x=\dfrac{2}{3}\)
\(c,\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-3}{10}\)
\(d,\dfrac{x}{3}-\dfrac{1}{2}=\dfrac{1}{5}\)
\(e,\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(h,x+30\%x=-1,3\)
\(k,3\dfrac{1}{3}x+16\dfrac{1}{4}=13,25\)
\(m,\dfrac{x-6}{2}=\dfrac{50}{x-6}\)
\(n,x-13,4=24,5-6,7.5,2\)
\(p,15,7x+3,6x=-96,5\)
\(q,2,5x-11,6=-59,1\)
\(\dfrac{2}{7}\)của\(\dfrac{-11}{6}\) \(\dfrac{3}{4}\) của 76 ki-lô-mét \(\dfrac{5}{8}\) của 96 tấn
0,25 của x giờ là 1 giờ thì x bằng? 3,7% của x là 13,5 thì x bằng?
giải chi tiết
A= ( -6,17 + \(3\dfrac{5}{9}\) - \(2\dfrac{36}{97}\)) . (\(\dfrac{1}{3}\) - 0,25 - \(\dfrac{1}{12}\))
B= \(\dfrac{0,5-\dfrac{3}{17}}{\dfrac{5}{6}-\dfrac{5}{17}}\) + \(\dfrac{0,5-\dfrac{1}{3}-0,2}{\dfrac{7}{5}+\dfrac{7}{3}-3,5}\)
Tìm x, biết:
a) \(\dfrac{-2}{5}\) + \(\dfrac{4}{5}\) . x = \(\dfrac{3}{5}\)
b) \(\dfrac{-3}{7}\) - \(\dfrac{4}{7}\) : x = \(\dfrac{2}{5}\)
c) \(\dfrac{4}{7}\) . x + \(\dfrac{2}{3}\) = \(\dfrac{-1}{5}\)
d) \(\dfrac{5}{7}\) : x -1 = \(\dfrac{2}{3}\)
Tìm x, biết:
a) \(\dfrac{2}{5}\) + \(\dfrac{3}{4}\): x = \(\dfrac{-1}{2}\)
b) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) . x = \(\dfrac{4}{5}\)
c) \(\dfrac{1}{2}\) x + \(\dfrac{2}{3}\) x = \(\dfrac{-2}{3}\)
d) \(\dfrac{4}{7}\)x - x= \(\dfrac{-9}{14}\)
\(\dfrac{x}{200}\)= \(\dfrac{1^2}{1.2}\) . \(\dfrac{2^2}{2.3}\) . \(\dfrac{3^2}{3.4}\) . .... .\(\dfrac{99^2}{99.100}\)