QA

\(\dfrac{312}{x}\)-\(\dfrac{312}{x+4}\)=\(\dfrac{1}{2}\)

NT
6 tháng 9 2021 lúc 13:49

Ta có: \(\dfrac{312}{x}-\dfrac{312}{x+4}=\dfrac{1}{2}\)

\(\Leftrightarrow x\left(x+4\right)=624x+2496-624x\)

\(\Leftrightarrow x^2+4x-2496=0\)

\(\Leftrightarrow\left(x+2\right)^2=2500\)

\(\Leftrightarrow\left[{}\begin{matrix}x=48\\x=-52\end{matrix}\right.\)

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