Question

\(\dfrac{2}{5}\)*\(15\dfrac{1}{3}\)-\(\dfrac{2}{5}\)*\(10\dfrac{1}{3}\)

\(12\dfrac{5}{11}\)-(\(3\dfrac{1}{4}\)+\(2\dfrac{5}{11}\)]

\(\dfrac{34}{31}\)-\(\dfrac{19}{28}\)-\(\dfrac{3}{31}\)

Answer 1

\(\dfrac{2}{5}\times15\dfrac{1}{3}-\dfrac{2}{5}\times10\dfrac{1}{3}\)

\(=\dfrac{2}{5}\times\left(15\dfrac{1}{3}-10\dfrac{1}{3}\right)\)

\(=\dfrac{2}{5}\times5\)

\(=2\)

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\(12\dfrac{5}{11}-\left(3\dfrac{1}{4}+2\dfrac{5}{11}\right)\)

\(=12\dfrac{5}{11}-3\dfrac{1}{4}-2\dfrac{5}{11}\)

\(=\left(12\dfrac{5}{11}-2\dfrac{5}{11}\right)-3\dfrac{1}{4}\)

\(=10-3\dfrac{1}{4}\)

\(=\dfrac{27}{4}\)

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\(\dfrac{34}{31}-\dfrac{19}{28}-\dfrac{3}{31}\)

\(=\left(\dfrac{34}{31}-\dfrac{3}{31}\right)-\dfrac{19}{28}\)

\(=\dfrac{31}{31}-\dfrac{19}{28}\)

\(=1-\dfrac{19}{28}\)

\(=\dfrac{9}{28}\)