\(\dfrac{2023^3-1}{2023^2+2024}=\dfrac{\left(2023-1\right)\left(2023^2+2023+1\right)}{2023^2+2024}\)
\(=\dfrac{2022\cdot\left(2023^2+2024\right)}{2023^2+2024}\)
=2022
Đúng 0
Bình luận (1)