\(=\dfrac{42}{60}\cdot\dfrac{10}{7}=1\)
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9 - 3 x ( X - 9 ) 64 + 6 x ( X + 1 ) 70dfrac{X}{13}+dfrac{15}{26}dfrac{46}{52}dfrac{11}{14}-dfrac{3}{X}dfrac{5}{14}5 x ( 3 + 7 x X ) 40X x 6 + 12 : 3 120X x 3,7 + X x 6,3 120( 15 x 24 - X ) : 0,25 100 : dfrac{1}{4}71 + 65 x 4 dfrac{X+140}{X}+ 260( X +1 ) + ( X + 4 ) + ( x + 7 ) + ...... + (X + 28 ) 155đây là bài tìm X
Đọc tiếp
9 - 3 x ( X - 9 ) = 6
4 + 6 x ( X + 1 ) 70
\(\dfrac{X}{13}+\dfrac{15}{26}=\dfrac{46}{52}\)
\(\dfrac{11}{14}-\dfrac{3}{X}=\dfrac{5}{14}\)
5 x ( 3 + 7 x X ) = 40
X x 6 + 12 : 3 = 120
X x 3,7 + X x 6,3 = 120
( 15 x 24 - X ) : 0,25 = 100 : \(\dfrac{1}{4}\)
71 + 65 x 4 = \(\dfrac{X+140}{X}\)+ 260
( X +1 ) + ( X + 4 ) + ( x + 7 ) + ...... + (X + 28 ) = 155
đây là bài tìm X
CN
20 tháng 9 2023 lúc 17:35
\(a,\dfrac{15-x}{14}=\dfrac{5}{7}\)
\(b,\dfrac{x}{9}=\dfrac{17}{3}\)
\(c,15-\dfrac{x}{2}=\dfrac{3}{7}\)
Tìm x
NT
24 tháng 9 2023 lúc 17:46
\(\dfrac{7}{13}\) : \(x\) = \(\dfrac{14}{39}\)
\(x\) x \(\dfrac{3}{5}\) = \(\dfrac{14}{15}\)
dfrac{15}{14} : dfrac{10}{21} x dfrac{1}{5}
5 x dfrac{1}{5} + dfrac{1}{5}
7 : dfrac{1}{5} - dfrac{1}{5}
6 + dfrac{1}{5} : 2
8 - dfrac{1}{5} x 7
Đọc tiếp
\(\dfrac{15}{14}\) : \(\dfrac{10}{21}\) x \(\dfrac{1}{5}\)
\(5\) x \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\)
\(7\) : \(\dfrac{1}{5}\) - \(\dfrac{1}{5}\)
\(6\) + \(\dfrac{1}{5}\) : \(2\)
\(8\) - \(\dfrac{1}{5}\) x \(7\)
a) dfrac{3}{7}+dfrac{4}{9}+dfrac{8}{14}+dfrac{10}{18}b) dfrac{1}{2}xdfrac{2}{3}:dfrac{5}{6}xdfrac{5}{6} bài này là bài tính bằng cách thuận tiện nhất nha !
Đọc tiếp
a) \(\dfrac{3}{7}\)+\(\dfrac{4}{9}\)+\(\dfrac{8}{14}\)+\(\dfrac{10}{18}\)
b) \(\dfrac{1}{2}\)x\(\dfrac{2}{3}\):\(\dfrac{5}{6}\)x\(\dfrac{5}{6}\)
bài này là bài tính bằng cách thuận tiện nhất nha !
a)dfrac{7}{8}xdfrac{3}{13}+dfrac{4}{9}xdfrac{4}{13}b)dfrac{6}{5}+dfrac{7}{3}+dfrac{8}{9}c)23: dfrac{5}{14}+dfrac{6}{7}+dfrac{4}{9}d)4dfrac{1}{4}+7dfrac{3}{7}-2dfrac{4}{17}e)8-(9dfrac{2}{11}+dfrac{8}{33})
Đọc tiếp
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
Tìm \(x\):
a)\(x\times\dfrac{4}{5}:2=\dfrac{6}{7}\) b)\(\dfrac{6}{5}:x:\dfrac{5}{4}=\dfrac{10}{15}\)
SC
16 tháng 10 2021 lúc 15:24
VÒNG 2Bài 1: Mèo con nhanh nhẹndfrac{1}{2} + dfrac{1}{12}2 + dfrac{1}{6}dfrac{1}{20}1 - dfrac{1}{9} dfrac{1}{15} + dfrac{2}{15}dfrac{1}{2} + dfrac{2}{3}dfrac{7}{12}dfrac{4}{12} dfrac{9}{14}+ dfrac{1}{14}1 + dfrac{1}{6}dfrac{1}{4} - dfrac{1}{5}dfrac{1}{3} - dfrac{2}{9} dfrac{3}{2} + dfrac{2}{3}dfrac{1}{5}1 - dfrac{8}{9} dfrac{5}{7}1 - dfrac{2}{3}dfrac{1}{3} + dfrac{5}{9}
Đọc tiếp
VÒNG 2
Bài 1: Mèo con nhanh nhẹn
| \(\dfrac{1}{2}\) + \(\dfrac{1}{12}\) | 2 + \(\dfrac{1}{6}\) | \(\dfrac{1}{20}\) | 1 - \(\dfrac{1}{9}\) | |
| \(\dfrac{1}{15}\) + \(\dfrac{2}{15}\) | \(\dfrac{1}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{7}{12}\) | \(\dfrac{4}{12}\) | |
| \(\dfrac{9}{14}\)+ \(\dfrac{1}{14}\) | 1 + \(\dfrac{1}{6}\) | \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) | \(\dfrac{1}{3}\) - \(\dfrac{2}{9}\) | |
| \(\dfrac{3}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{1}{5}\) | 1 - \(\dfrac{8}{9}\) | ||
| \(\dfrac{5}{7}\) | 1 - \(\dfrac{2}{3}\) | \(\dfrac{1}{3}\) + \(\dfrac{5}{9}\) |
Bài 1: tính
a) 3dfrac{1}{2} + 4dfrac{5}{7} - 5dfrac{5}{14} b) 4dfrac{1}{2} + dfrac{1}{2} : 5dfrac{1}{2}
bài 2: tìm X
a) X x 3dfrac{1}{3} 3dfrac{1}{3} : 4dfrac{1}{4} b) 5dfrac{2}{3} : X 3dfrac{2}{3} - 2dfrac{1}{2}
các giáo viên olm giúp e vs, e cần gấp lắm!
Đọc tiếp
Bài 1: tính
a) 3\(\dfrac{1}{2}\) + 4\(\dfrac{5}{7}\) - 5\(\dfrac{5}{14}\) b) 4\(\dfrac{1}{2}\) + \(\dfrac{1}{2}\) : \(5\dfrac{1}{2}\)
bài 2: tìm X
a) X x \(3\dfrac{1}{3}\) = \(3\dfrac{1}{3}\) : \(4\dfrac{1}{4}\) b) \(5\dfrac{2}{3}\) : X = \(3\dfrac{2}{3}\) - \(2\dfrac{1}{2}\)
các giáo viên olm giúp e vs, e cần gấp lắm!