Question

\(\dfrac{1}{3}+\dfrac{2}{3}.x=\dfrac{4}{3}\)

\(\dfrac{3}{5}.x+\dfrac{1}{4}=\dfrac{1}{10}\)

Answer 1

`1/3+2/3 .x=4/3`

`2/3 .x =1`

`x=3/2`

.

`3/5 x+1/4=1/10`

`3/5 x=-3/20`

`x=-1/4`

Answer 2

a) Ta có: \(\dfrac{1}{3}+\dfrac{2}{3}\cdot x=\dfrac{4}{3}\)

\(\Leftrightarrow x\cdot\dfrac{2}{3}=1\)

hay \(x=\dfrac{3}{2}\)

b) Ta có: \(\dfrac{3}{5}x+\dfrac{1}{4}=\dfrac{1}{10}\)

\(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{10}-\dfrac{1}{4}=\dfrac{-6}{10}=\dfrac{-3}{5}\)

hay x=-1

Answer 3

a)\(\dfrac{1}{3}x+\dfrac{2}{3}x=\dfrac{4}{3} \)

\(\Leftrightarrow\)\(x=\dfrac{4}{3}\)

b)\(\dfrac{3}{5}x+\dfrac{1}{4}=\dfrac{1}{10}\)

\(\Leftrightarrow\)\(\dfrac{3}{5}x=-\dfrac{3}{20}\)

\(\Leftrightarrow\)\(x=-\dfrac{1}{4}\)