Question

\(\dfrac{-7}{2}\times\dfrac{4}{11}+\dfrac{7}{14}\times\dfrac{-7}{2}+\dfrac{13}{2}=\)?

Answer 1

\(=\dfrac{-7}{2}\left(\dfrac{4}{11}+\dfrac{1}{2}\right)+\dfrac{13}{2}\)

\(=\dfrac{-7}{2}\cdot\dfrac{19}{22}+\dfrac{13}{2}\)

\(=\dfrac{153}{44}\)