\(=\dfrac{2021}{2022}\left(\dfrac{6}{17}-\dfrac{23}{17}\right)+\dfrac{2021}{2022}=\dfrac{-2021}{2022}+\dfrac{2021}{2022}=0\)
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Các câu hỏi tương tự
A = \(\dfrac{2022}{2021^{2^{ }}+1}\) + \(\dfrac{2022}{2021^{2^{ }}+2}\) + \(\dfrac{2022}{2021^2+3}\) + ... + \(\dfrac{2022}{2021^{2^{ }}+2021}\)
Chứng tỏ rằng A không phải số tự nhiên
so sánh
a)A=\(\dfrac{17^{18}+1}{17^{19}+1}\)và B=\(\dfrac{17^{17}+1}{17^{18}+1}\)
b)C=\(\dfrac{2^{2020}-1}{2^{2021}-1}\)và D=\(\dfrac{2^{2021}-1}{2^{2022}-1}\)
c)\(\dfrac{13579}{34567}\)và \(\dfrac{13580}{34569}\)
Giúp mình với nhé😌
NV
7 tháng 5 2023 lúc 17:05
Cho A = \(\dfrac{2019}{2020}\)+\(\dfrac{2020}{2021}\)+\(\dfrac{2021}{2022}\)+\(\dfrac{2022}{2019}\). Chứng tỏ A > 4
Giúp với ạ!!
TN
20 tháng 4 2022 lúc 22:36
giúp mk, please :)
\(\dfrac{\dfrac{1}{6}+\dfrac{1}{7}+...+\dfrac{1}{2022}}{2017+\dfrac{2016}{6}+\dfrac{2015}{7}+...+\dfrac{1}{2021}}\)
A. \(\dfrac{1}{2020}\)
B. \(\dfrac{1}{2021}\)
C. \(\dfrac{1}{2019}\)
D. \(\dfrac{1}{2022}\)
chọn ra 3 ngừi nhanh nhứt:>>
MN
9 tháng 5 2022 lúc 9:56
Tìm x, biết:
( \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{4}\) + ... + \(\dfrac{1}{2023}\) ) . x = \(\dfrac{2022}{1}\) + \(\dfrac{2021}{2}\) + \(\dfrac{2020}{3}\)
+ ... + \(\dfrac{1}{2022}\)
\(t=\dfrac{1}{2^1}+\dfrac{2}{2^2}+\dfrac{3}{2^3}+...+\dfrac{2021}{2^{2021}}+\dfrac{2022}{2^{2022}}\)
CHỨNG TỎ T < 2
KH
3 tháng 3 2023 lúc 22:57
So sánh:
a) A=\(\dfrac{98^{88}+1}{98^{98}+1}\)và B=\(\dfrac{98^{89}+1}{98^{99}+1}\) b) C=\(\dfrac{2022^{2023}+1}{2022^{2021}+1}\)và D=\(\dfrac{2022^{2021}+1}{2022^{2019}+1}\)
\(\dfrac{x+1}{2022}\)+\(\dfrac{x+2}{2021}\)+.....+\(\dfrac{x+23}{2000}\)+23=0
Mọi người giúp mik vs ạ,mai mik phải nộp rồi ạ!
\(\dfrac{2}{3}\).\(\dfrac{2022}{2021}\)-\(\dfrac{2}{3}\).\(\dfrac{1}{2021}\)+\(\dfrac{1}{3}\)