Question

\((\dfrac{-1}{4})^2-3,5+\sqrt{7}\)

Answer 1

\(=\dfrac{1}{16}-\dfrac{7}{2}+\sqrt{7}=\dfrac{-55}{16}+\sqrt{7}\)

Answer 2

\(\left(-\dfrac{1}{4}\right)^2-3,5+\sqrt{7}\\ =\dfrac{1}{16}-3,5+\sqrt{7}\\ =-\dfrac{55}{16}+\sqrt{7}\\ =\dfrac{-55+16\sqrt{7}}{16}\)

Answer 3

= \(\dfrac{1}{16}-3,5+\)√7

= \(\dfrac{-55+16\sqrt{7}}{16}\)