\(BTKL\Rightarrow m_O=1,6\left(g\right)\Rightarrow n_O=0,1\left(mol\right)\\ n_{SO_2}=0,2\left(mol\right)\\ BT\text{ }e\Rightarrow3n_{Fe}=2n_O+2n_{SO_2}=0,6\left(mol\right)\\ \Rightarrow n_{Fe}=0,2\left(mol\right)\Rightarrow m_{Fe}=11,2\left(g\right)\)