Question

Đạo hàm \(\sqrt{4x+\sqrt{4x+9}}\)

Answer 1

\(y'=\dfrac{\left(4x+\sqrt{4x+9}\right)'}{2\sqrt{4x+\sqrt{4x+9}}}=\dfrac{4+\left(\sqrt{4x+9}\right)'}{2\sqrt{4x+\sqrt{4x+9}}}\)

\(=\dfrac{4+\dfrac{2}{\sqrt{4x+9}}}{2\sqrt{4x+\sqrt{4x+9}}}=\dfrac{1+2\sqrt{4x+9}}{\sqrt{4x+\sqrt{4x+9}}.\sqrt{4x+9}}\)