Question

d,
8^110x(-9)^71/6^143x4^94

Answer 1

\(=\dfrac{-2^{330}\cdot3^{142}}{2^{143}\cdot3^{143}\cdot2^{188}}=\dfrac{-1}{2}\cdot\dfrac{1}{3}=-\dfrac{1}{6}\)

Answer 2

\(\dfrac{8^{110}\cdot\left(-9\right)^{71}}{6^{143}\cdot4^{94}}=\dfrac{\left(2^3\right)^{110}\cdot\left[\left(-3\right)^2\right]^{71}}{\left(2\cdot3\right)^{143}\cdot\left(2^2\right)^{94}}=\dfrac{2^{330}\cdot\left(-3\right)^{142}}{2^{143}\cdot3^{143}\cdot2^{188}}=\dfrac{-1}{2\cdot3}=-\dfrac{1}{6}\)