Để:
\(A\inℤ\)
\(\Leftrightarrow n+8⋮2n-4\)
\(n+8⋮2\left(n-2\right)\)
\(n+8⋮n+2\)
\(n-2+10⋮n-2\)
\(10⋮n-2\)
\(\Rightarrow n-2\inƯ\left(10\right)=\left\{\pm1;\pm2;\pm5;\pm10\right\}\)
\(\Rightarrow n\in\left\{3;1;4;0;7;-3;12;-8\right\}\)
Vậy \(\Rightarrow n\in\left\{3;1;4;0;7;-3;12;-8\right\}\) để \(A\) nguyên.