\(x^2-2mx+m^2-4=0\)
\(\Delta'=m^2-m^2=4=4\Rightarrow\) pt luôn có 2 nghiệm: \(\left\{{}\begin{matrix}x=m+2\\x=m-2\end{matrix}\right.\)
TH1: \(\left\{{}\begin{matrix}x_1=m+2\\x_2=m-2\end{matrix}\right.\)
\(\Rightarrow\left|2m+4-m+2\right|>2018\Rightarrow\left|m+6\right|>2018\)
\(\Rightarrow\left[{}\begin{matrix}m+6>2018\\m+6< -2018\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}m>2012\\m< -2024\end{matrix}\right.\)
TH2: \(\left\{{}\begin{matrix}x_1=m-2\\x_2=m+2\end{matrix}\right.\)
\(\Rightarrow\left|2m-4-m-2\right|>2018\Leftrightarrow\left|m-6\right|>2018\)
\(\Rightarrow\left[{}\begin{matrix}m-6< 2018\\m-6< -2018\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}m>2024\\m< -2012\end{matrix}\right.\)