`@TH1`
Nếu `M ;N in AB` thì
`AM + BN + MN =AB`
`=> MN = AB - (AM + BN) = 8 -(2+1) `
`MN =5cm`
Vậy `MN =5cm`
`@TH2`
Nếu `M;N` nằm ngoài `AB` thì
`MN = AM + AB +BN`
Mà `AM =1cm ; AB = 8cm;BN=2cm`
`=> MN = 1+8+2 = 11(cm)`
Vậy `MN=11cm`
BM=8-2=6cm
MN=BM-NB=6-1=5cm