Question

Cho hàm số a)y=f(x)=3x² + x +1 Tính f(1) ; f(-1/3) ; f(2/3) ; f(-2); f(-4/3)

Answer 1

\(f\left(1\right)=3\cdot1^2+1+1=5\\ f\left(-\dfrac{1}{3}\right)=3\cdot\left(-\dfrac{1}{3}\right)^2-\dfrac{1}{3}+1=\dfrac{1}{3}-\dfrac{1}{3}+1=1\\ f\left(\dfrac{2}{3}\right)=3\cdot\left(\dfrac{2}{3}\right)^2+\dfrac{2}{3}+1=\dfrac{4}{3}+\dfrac{2}{3}+1=3\\ f\left(-2\right)=3\left(-2\right)^2-2+1=12-2+1=11\\ f\left(-\dfrac{4}{3}\right)=3\cdot\left(-\dfrac{4}{3}\right)^2-\dfrac{4}{3}+1=\dfrac{16}{3}-\dfrac{4}{3}+1=5\)

Answer 2

\(f\left(1\right)=3\cdot1^2+1+1=5\)

\(f\left(-\dfrac{1}{3}\right)=3\cdot\dfrac{1}{9}-\dfrac{1}{3}+1=1\)

\(f\left(\dfrac{2}{3}\right)=3\cdot\dfrac{4}{9}+\dfrac{2}{3}+1=3\)