Question

Cho don thuc K=1/5x^3y(-x^4yz^3)^2

AIgiup mk voi

Answer 1

\(K=\dfrac{1}{5}x^3y\left(-x^4yz^3\right)^2\)

    \(=\dfrac{1}{5}x^3y\left(x^8y^2z^6\right)\)

    \(=\dfrac{1}{5}x^{11}y^3z^6\)

Answer 2

\(K=\dfrac{1}{5}x^3y\cdot\left(-x^4yz^3\right)^2\)

\(=\dfrac{1}{5}x^3y\cdot x^8y^2z^6\)

\(=\dfrac{1}{5}x^{11}y^3z^6\)