Đặt a/b=c/d=k
=>a=bk; c=dk
\(\dfrac{a+b}{a}=\dfrac{bk+b}{bk}=\dfrac{k+1}{k}\)
\(\dfrac{c+d}{c}=\dfrac{dk+d}{d}=\dfrac{k+1}{k}\)
=>(a+b)/a=(c+d)/c
Đúng 2
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Ta có: \(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Rightarrow\text{ }\dfrac{b}{a}=\dfrac{d}{c}\)
\(\Rightarrow\text{ }\dfrac{b}{a}+1=\dfrac{d}{c}+1\)
\(\Rightarrow\text{ }\dfrac{b+a}{a}=\dfrac{d+c}{c}\)
\(\Leftrightarrow\text{ }\dfrac{a+b}{a}=\dfrac{c+d}{c}\) (đpcm)
Đúng 3
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