Question

Cho \(\dfrac{2y+2z-x}{a}=\dfrac{2z+2x-y}{b}=\dfrac{2z+2y-z}{c}\)

CMR: \(\dfrac{x}{2b+2c-a}=\dfrac{y}{2c-2a-b}=\dfrac{z}{2a-2b-c}\)