a: \(BD\cdot CE\cdot BC=\dfrac{BH^2}{BA}\cdot\dfrac{CH^2}{CA}\cdot\dfrac{AB\cdot AC}{AH}\)
\(=\dfrac{AH^4}{AH}=AH^3=DE^3\)
b: \(\dfrac{BD}{CE}=\dfrac{BH^2}{BA}:\dfrac{CH^2}{CA}=\left(\dfrac{BH}{CH}\right)^2\cdot\dfrac{CA}{BA}\)
\(=\dfrac{BA^4\cdot CA}{CA^4\cdot BA}=\dfrac{BA^3}{CA^3}\)