Question

Cho biểu thức A = (\(\dfrac{2\sqrt{x}+x}{x\sqrt{x}-1}\) - \(\dfrac{1}{x+\sqrt{x}+1}\)) : (\(\dfrac{x-1}{x+\sqrt{x}+1}\))

a, Rút gọn biểu thức A

b, Tính A khi x = 5 + 2\(\sqrt{3}\)

c, Tìm x để |A| ≤ 1

Answer 1

\(a,A=\dfrac{2\sqrt{x}+x-\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\cdot\dfrac{x+\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ A=\dfrac{x+\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\cdot\dfrac{x+\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ A=\dfrac{x+\sqrt{x}+1}{\left(\sqrt{x}-1\right)^2\left(\sqrt{x}+1\right)}\)