Question

Cho A = \(\dfrac{x+2\sqrt{x}}{x}\); B = \(\dfrac{\sqrt{x}+2}{\sqrt{x}+1}\)(ĐKXĐ: x > 0). Tìm x nguyên để \(\dfrac{A}{B}< \dfrac{7}{4}\).

Answer 1

\(P=\dfrac{A}{B}=\sqrt{x}+1\)

P<7/4

=>căn x<3/4

=>0<x<9/16