Question

cho A=\( \dfrac{x-2}{2+\sqrt{x}}\)(x>=0), B=\({\dfrac{8x-4}{2x+1}}\)(x>0, x khác \( \dfrac{1}{2}\), x khác \(​​\dfrac{-1}{2}\))

tìm x để \(\dfrac{A}{B}=1\)