Question

cho 3 đa thức A(x)=x^3-3x^2+5x-3

B(x)=-x^3+2x^2-3x+5

C(x)=x-3

a)......

b) tính A(x) nhân C(x)

c)B(x):C(x) THEO CỘT ĐỌC

d)A(x)-B(x)

d)

 

Answer 1

b: A(x)*C(x)

=(x^3-3x^2+5x-3)(x-3)

=x^4-3x^3-3x^3+9x^2+5x^2-15x-3x+9

=x^4-6x^3+14x^2-18x+9

c: B(x):C(x)

\(=\dfrac{-x^3+3x^2-x^2+3x-6x+18-13}{x-3}\)

=-x^3-x-6-13/x-3

d: A(x)-B(x)

=x^3-3x^2+5x-3+x^3-2x^2+3x-5

=2x^3-5x^2+8x-8