h: \(x^2-\left|x\right|-6=0\)=>\(\left(\left|x\right|\right)^2-\left|x\right|-6=0\)=>\(\left(\left|x\right|-3\right)\left(\left|x\right|+2\right)=0\)=>\(\left|x\right|-3=0\)=>|x|=3=>\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)Câu trả lời: h: \(x^2-\left|x\right|-6=0\)=>\(\left(\left|x\right|\right)^2-\left|x\right|-6=0\)=>\(\left(\left|x\right|-3\right)\left(\left|x\right|+2\right)=0\)=>\(\left|x\right|-3=0\)=>|x|=3=>\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)