Câu 1:
a) Ư(-12)={1;-1;2;-2;3;-3;4;-4;6;-6;12;-12}
b) B(-4)={0;-4;-8;4;8;...}
Câu 2:
a) Ta có: \(x-15=11-\left(-32\right)\)
\(\Leftrightarrow x-15=11+32\)
\(\Leftrightarrow x=43+15=58\)
Vậy: x=58
b) Ta có: \(13-\left(5-x\right)=7\)
\(\Leftrightarrow13-5+x=7\)
\(\Leftrightarrow x+8=7\)
hay x=-1
Vậy: x=-1
c) Ta có: \(x-\dfrac{3}{5}=5.12\)
\(\Leftrightarrow x-0.6=5.12\)
hay x=5,72
Vậy: x=5,72
d) Ta có: \(\dfrac{x+1}{-2}=\dfrac{-8}{x+1}\)
\(\Leftrightarrow\left(x+1\right)^2=\left(-2\right)\cdot\left(-8\right)=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-5\right\}\)
a,Ư(-12)={1,-1,2,-2,3,-3,4,-4,6,-6,12,-12}
b,5 bội của 4 là:0,5,10,-10,-5
câu 2:
a,x-15=43 b,5-x=13-7 c,x-3/5=5,12
x=43+15 5-x=6 x-3/5=128/25
x=58 x=5-6 x=128/25+3/5
x=-1 x=143/25
Câu 1:
a,Ư(-12): 1; -1; 2; -2; 3; -3; 4; -4; 6; -6; 12; -12.
b,B(-4): 8; -8; 16; -16; 32;.....
Câu 2:
a, x-15=11-(-32) b,13-[5-x]= 7
x-15=43 5-x=13-7
x=43+15 5-x=6
x=58 x=6-5
Vậy x=58. x=1
Vậy x=1.
c, x-3/5= 5,12 d, x+1/-2=-8/x+1
x-3=5,12/5 2(x+1)=(-8)/(-2)
x-3=1,024 2(x+1)=4
x=1,024+3 x+1=4/2
x=4,024. x+1=2
Vậy x=4,024. x=2-1
x=1.
Vậy x=1.