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cần giúp với ạ, em cảm ơn

NT
17 tháng 12 2023 lúc 21:59

a: (x+1)(x-5)=0

=>\(\left[{}\begin{matrix}x+1=0\\x-5=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=-1\\x=5\end{matrix}\right.\)

b: \(\left(x+2\right)\left(-x-5\right)=0\)

=>\(-1\cdot\left(x+2\right)\left(x+5\right)=0\)

=>(x+2)(x+5)=0

=>\(\left[{}\begin{matrix}x+2=0\\x+5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-5\end{matrix}\right.\)

c: \(\left(x-2024\right)\left(4x+8\right)=0\)

=>\(4\cdot\left(x+2\right)\left(x-2024\right)=0\)

=>(x+2)(x-2024)=0

=>\(\left[{}\begin{matrix}x+2=0\\x-2024=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=2024\end{matrix}\right.\)

d: (x+1)(2x-6)=0

=>2(x-3)(x+1)=0

=>(x-3)(x+1)=0

=>\(\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

e: (2x+10)(4x+20)=0

=>\(2\left(x+5\right)\cdot4\left(x+5\right)=0\)

=>\(8\left(x+5\right)^2=0\)

=>\(\left(x+5\right)^2=0\)

=>x+5=0

=>x=-5

h: \(\left(-24+x\right)\left(4x-8\right)=0\)

=>\(4\cdot\left(x-2\right)\cdot\left(x-24\right)=0\)

=>\(\left(x-2\right)\left(x-24\right)=0\)

=>\(\left[{}\begin{matrix}x-2=0\\x-24=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=24\end{matrix}\right.\)

i: (4x-100)(3x-6)=0

=>\(\left[{}\begin{matrix}4x-100=0\\3x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=100\\3x=6\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=25\\x=2\end{matrix}\right.\)

k: (-7-x)(4x-36)=0

=>\(\left(-1\right)\cdot\left(x+7\right)\cdot4\left(x-9\right)=0\)

=>\(\left(x+7\right)\left(x-9\right)=0\)

=>\(\left[{}\begin{matrix}x+7=0\\x-9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-7\\x=9\end{matrix}\right.\)

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DH
17 tháng 12 2023 lúc 22:35

cảm ơn

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