AD

Bài 6: Tính

a, (6\(\dfrac{4}{9}\) + 3\(\dfrac{7}{11}\)) - 4\(\dfrac{4}{9}\)

b, -1\(\dfrac{1}{3}\) - 2\(\dfrac{5}{6}\) . \(\dfrac{6}{11}\) + 3 : 5%

c, \(\dfrac{2}{3.5}\) +  \(\dfrac{2}{5.7}\) + \(\dfrac{2}{7.9}\) + ... + \(\dfrac{2}{97.99}\)

d, \(\dfrac{5}{7}\)\(\dfrac{5}{11}\) + \(\dfrac{5}{7}\) . \(\dfrac{2}{11}\) -  \(\dfrac{5}{7}\)\(\dfrac{14}{11}\)

KL
25 tháng 4 lúc 15:12

a) \(\left(6\dfrac{4}{9}+3\dfrac{7}{11}\right)-4\dfrac{4}{9}\)

\(=6+\dfrac{4}{9}+3+\dfrac{7}{11}-4-\dfrac{4}{9}\)

\(=\left(6+3-4\right)+\left(\dfrac{4}{9}-\dfrac{4}{9}\right)+\dfrac{7}{11}\)

\(=5+\dfrac{7}{11}\)

\(=\dfrac{62}{11}\)

b) \(-1\dfrac{1}{3}-2\dfrac{5}{6}.\dfrac{6}{11}+3:5\%\)

\(=-\dfrac{4}{3}-\dfrac{17}{6}.\dfrac{6}{11}+3:\dfrac{1}{20}\)

\(=-\dfrac{4}{3}-\dfrac{17}{11}+60\)

\(=-\dfrac{95}{33}+60\)

\(=\dfrac{1885}{33}\)

c) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{97.99}\)

\(=\dfrac{5-3}{3.5}+\dfrac{7-5}{5.7}+\dfrac{9-7}{7.9}+...+\dfrac{99-97}{97.99}\)

\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{97}-\dfrac{1}{99}\)

\(=\dfrac{1}{3}-\dfrac{1}{99}\)

\(=\dfrac{32}{99}\)

d) \(\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)

\(=\dfrac{5}{7}.\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)\)

\(=\dfrac{5}{7}.\left(-\dfrac{7}{11}\right)\)

\(=-\dfrac{5}{11}\)

Bình luận (0)
H24
25 tháng 4 lúc 15:28

`a)(6 4/9+3 7/11)-4 4/9`

`=(6+4/9+3+7/11)-4-4/9`

`=6+4/9+3+7/11-4-4/9`

`=(6-4+3)+(4/9-4/9)+7/11`

`=5+7/11`

`=55/11+7/11`

`=62/11`

_

`b)-1 1/3-2 5/6 . 6/11+3:5%`

`=-4/3-17/6 . 6/11+60`

`=-4/3-17/11+60`

`=1885/33`

_

`c)2/3.5+2/5.7+2/7.9+..+2/97.99`

`=1/3-1/5+1/5-1/7+1/7-1/9+...+1/97-1/99`

`=1/3-1/99`

`=32/99`

_

`d)5/7 . 5/11+5/7 . 2/11-5/7 . 14/11`

`=5/7(5/11+2/11-14/11)`

`=5/7 . (-7)/11`

`=-5/11`

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