a) \(A=x^2+2x+2\)
\(=x^2+2x+1+1\)
\(=\left(x+1\right)^2+1>0\forall x\)
b) \(B=4x^2-4x+11\)
\(=4x^2-4x+1+10\)
\(=\left(2x-1\right)^2+10>0\forall x\)
c) \(C=x^2-x+1\)
\(=x^2-2\cdot x\cdot\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{3}{4}\)
\(=\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}>0\forall x\)
d) Ta có: \(D=x^2-2x+y^2+4y+6\)
\(=x^2-2x+1+y^2+4y+4+1\)
\(=\left(x-1\right)^2+\left(y+2\right)^2+1>0\forall x,y\)
e) Ta có: \(D=x^2-2xy+y^2+x^2-8x+20\)
\(=x^2-2xy+y^2+x^2-8x+16+4\)
\(=\left(x-y\right)^2+\left(x-4\right)^2+4>0\forall x,y\)
\(A=x^2+2x+2=\left(x+1\right)^2+1\ge1>0\left(\forall x\right)\)
\(B=4x^2-4x+11=\left(2x-1\right)^2+10\ge10>0\left(\forall x\right)\)
\(C=x^2-x+1=x^2-2.\dfrac{1}{2}x+\dfrac{1}{4}+\dfrac{3}{4}=\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}>0\)
\(D=x^2-2x+y^2+4y+6=x^2-2x+1+y^2+4y+4+1\)
\(=\left(x-1\right)^2+\left(y-2\right)^2+1\ge1>0\)
\(E=x^2-2xy+y^2+x^2-8x+16+4\)
\(=\left(x-y\right)^2+\left(x-4\right)^2+4\ge4>0\)\(\left(\forall x,y\right)\)