Question

Bài 2 : Viết gọn dưới dạng một lũy thừa :

e ) \(4.32.\left(2^3.\dfrac{1}{16}\right)^2\)             f )  \(\left(\dfrac{1}{57}\right)^2.\left(\dfrac{1}{7}\right).49^2\)

Answer 1

e: \(=2^2\cdot2^5\cdot\left(\dfrac{1}{2}\right)^2=2^7\cdot\dfrac{1}{2^2}=2^5\)

f: \(=\left(\dfrac{1}{57}\right)^2\cdot\dfrac{1}{7}\cdot7^4=\dfrac{7^3}{57^2}\)

Answer 2

e) \(4.32.\left(2^3.\dfrac{1}{16}\right)^2=2^2.2^5.\left(2^3.\dfrac{1}{2^4}\right)^2=2^7.2^6.\dfrac{1}{2^8}=2^5=32\)

f) \(\left(\dfrac{1}{57}\right)^2.\dfrac{1}{7}.49^2=\left(\dfrac{1}{57}\right)^2.\dfrac{1}{7}.7^4=\left(\dfrac{1}{57}\right)^2.7^2.7=\left(\dfrac{1}{57}.7\right)^2.7=\left(\dfrac{7}{57}\right)^2.7\)

Answer 3

\(4.32.\left(2^3.\dfrac{1}{16}\right)^2=128.\dfrac{1}{4}=32=2^5\)

\(\left(\dfrac{1}{57}\right)^2.\dfrac{1}{7}.49^2=\dfrac{1}{3249}.\dfrac{1}{7}.2401=\dfrac{2401}{3249}=\dfrac{7^4}{57^2}\)