Bài 1: Thực hiện phép tính:
1, \(\dfrac{3}{2}-\left|\dfrac{-1}{12}\right|-\left(2-\dfrac{1}{3}\right)^2\)
2, \(\left(\dfrac{2}{3}-0,25\right).\left(\dfrac{-2}{5}\right)^2-\left(1\dfrac{2}{5}+1\dfrac{1}{3}-2\right)\)
3, \(\left(\dfrac{-1}{3}\right)^2-\dfrac{1}{12}+\left|\dfrac{-5}{18}\right|\)
\(4,\left|\dfrac{-2}{5}-\dfrac{1}{2}\right|+\dfrac{-3}{5}-\dfrac{3^2}{20}\)
5, \(\left(1+\dfrac{2}{3}-\dfrac{14}{9}\right):\left(\dfrac{5}{6}-\dfrac{4}{5}\right)^2\)
1: \(=\dfrac{3}{2}-\dfrac{1}{12}-\dfrac{25}{9}=\dfrac{54}{36}-\dfrac{3}{36}-\dfrac{100}{36}=\dfrac{-49}{36}\)
2: \(=\left(\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\dfrac{4}{25}-\left(\dfrac{7}{5}+\dfrac{4}{3}-2\right)\)
\(=\dfrac{5}{12}\cdot\dfrac{4}{25}-\dfrac{21+20-30}{15}\)
\(=\dfrac{1}{15}-\dfrac{11}{15}=\dfrac{-10}{15}=-\dfrac{2}{3}\)
3: \(=\dfrac{1}{9}-\dfrac{1}{12}+\dfrac{5}{18}=\dfrac{4}{36}-\dfrac{3}{36}+\dfrac{10}{36}=\dfrac{11}{36}\)
