Question

bài 1: phân tích đa thức thành nhân tử

a)x^2-y^2+2x+1

b)(x+9)^2-36x^2

c)x^2-2xy+y^2-z^2+2zt-t^2

d)x^3-3x^2+3x+1-y^3

Answer 1

a)\(=\left(x^2+2x+1\right)-y^2=\left(x+1\right)^2-y^2=\left(x+1+y\right)\left(x+1-y\right)\)

b)\(=\left(x+9\right)^2-\left(6x\right)^2=\left(x+9-6x\right)\left(x+9+6x\right)=\left(-5x+9\right)\left(7x+9\right)\)

c)\(=\left(x^2-2xy+y^2\right)-\left(z^2-2zt+t^2\right)=\left(x-y\right)^2-\left(z-t\right)^2\\ =\left(x-y+z-t\right)\left(x-y-z+t\right)\)

 

Answer 2

a: =(x+1-y)(x+1+y)