Question

bài 1 

a) x-8/2 -x/10 = 4

b) x-1/x +2x-2/x(x-2)=0

Answer 1

a) Ta có: \(\dfrac{x-8}{2}-\dfrac{x}{10}=4\)

\(\Leftrightarrow\dfrac{5\left(x-8\right)}{10}-\dfrac{x}{10}=\dfrac{40}{10}\)

\(\Leftrightarrow5x-40-x=40\)

\(\Leftrightarrow4x=80\)

hay x=20

Vậy: S={20}

Answer 2

b)

ĐKXĐ: \(x\notin\left\{0;2\right\}\)

Ta có: \(\dfrac{x-1}{x}+\dfrac{2x-2}{x\left(x-2\right)}=0\)

\(\Leftrightarrow\dfrac{\left(x-1\right)\left(x-2\right)}{x\left(x-2\right)}+\dfrac{2x-2}{x\left(x-2\right)}=0\)

Suy ra: \(x^2-3x+2+2x-2=0\)

\(\Leftrightarrow x^2-x=0\)

\(\Leftrightarrow x\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\x=1\left(nhận\right)\end{matrix}\right.\)

Vậy: S={1}