Question

bài 1:

a) \(\sqrt{4-2\sqrt{3}}\) -\(\sqrt{3}\) b) \(\sqrt{10-2\sqrt{21}}\) +\(\sqrt{7}\)

c) \(\sqrt{6-4\sqrt{2}-}\sqrt{10}\) d) \(\sqrt{4-2\sqrt{28}}\) +2

bài 2: rút gọn bt

a) \(\sqrt{12-6\sqrt{3}}-3\) b) \(\sqrt{7+2\sqrt{6}}-\sqrt{3}\)

c) \(\sqrt{11-2\sqrt{10}}-\sqrt{10}\) d) \(\sqrt{9-2\sqrt{20}}+\sqrt{5}\)

Answer 1

mình làm mẫu 2 bài nhé 2 bài kia bạn làm tương tự

1)a)\(\sqrt{4-2\sqrt{3}}-\sqrt{3}=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{3}=\sqrt{3}+1-\sqrt{3}=1\)

\(\sqrt{10-2\sqrt{21}}+\sqrt{7}=\sqrt{\left(\sqrt{7}+\sqrt{3}\right)^2}+\sqrt{7}=\sqrt{7}+\sqrt{3}+\sqrt{7}=2\sqrt{7}+\sqrt{3}\)

2)a) \(\sqrt{12-6\sqrt{3}}-\sqrt{3}=\sqrt{\left(3-\sqrt{3}\right)^2}-\sqrt{3}=3-\sqrt{3}-\sqrt{3}=3-2\sqrt{3}\)

b) \(\sqrt{7+2\sqrt{6}}-\sqrt{3}=\sqrt{\left(1+\sqrt{6}\right)^2}-\sqrt{3}=1+\sqrt{6}-\sqrt{3}\)