Question

b)(3x -2)(x +3)+(x^2 -9)=0

Answer 1

\(\Leftrightarrow\left(x+3\right)\left(3x-2+x-3\right)=0\)

\(\Leftrightarrow\left(x+3\right)\left(4x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{5}{4}\end{matrix}\right.\)