Question

B = -1/99 - 1/99.98 - 1/98.97 - 1/97.96 - ... - 1/3.2 - 1/2.1

Answer 1

\(B=-\dfrac{1}{99}-\dfrac{1}{99.98}-\dfrac{1}{98.98}-...-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)

\(B=-\left(\dfrac{1}{99}+\dfrac{1}{99.98}+\dfrac{1}{98.97}+...+\dfrac{1}{3.2}+\dfrac{1}{2.1}\right)\)

\(B=-\left(\dfrac{1}{99}+\dfrac{1}{98}-\dfrac{1}{99}+\dfrac{1}{97}-\dfrac{1}{98}+...+\dfrac{1}{2}-\dfrac{1}{3}+1-\dfrac{1}{2}\right)\)

\(B=-1\)