Question

ai giúp mình với ạ

Answer 1

\(4,2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ \Rightarrow m_{Fe(OH)_3}=m_{Fe_2O_3}+m_{H_2O}=214(g)\\ \Rightarrow \%_{phân hủy}=\dfrac{214}{400}.100\%=53,5\%\\ \Rightarrow A\\ 5,M_A=\dfrac{9,6}{0,15}=64(g/mol)\\ \Rightarrow A:Cu\\ \Rightarrow A\)

Answer 2

Câu 4: B

Câu 5: B