TH

a.\(\dfrac{6}{7}\):(\(\dfrac{-1}{8}\))+\(\dfrac{6}{7}\).\(\dfrac{3}{4}\)

b.[\(\dfrac{3}{5}\)+(\(\dfrac{-1}{4}\))]:\(\dfrac{3}{7}\)+[(\(\dfrac{-3}{7}\)+\(\dfrac{2}{5}\))]:\(\dfrac{3}{7}\)

c.\(\dfrac{7}{8}\):(\(\dfrac{2}{9}\)-\(\dfrac{1}{18}\))+\(\dfrac{7}{8}\):(\(\dfrac{1}{36}\)-\(\dfrac{5}{12}\))

H9
10 tháng 7 2024 lúc 12:10

\(a)\dfrac{6}{7}:\left(\dfrac{-1}{8}\right)+\dfrac{6}{7}\cdot\dfrac{3}{4}\\ =\dfrac{6}{7}\cdot\left(-8\right)+\dfrac{6}{7}\cdot\dfrac{3}{4}\\ =\dfrac{6}{7}\cdot\left(\dfrac{3}{4}-8\right)\\ =\dfrac{6}{7}\cdot\dfrac{-29}{4}\\ =\dfrac{-87}{14}\\ b)\left[\dfrac{3}{5}+\left(\dfrac{-1}{4}\right)\right]:\dfrac{3}{7}+\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}\\ =\left(\dfrac{3}{5}+\dfrac{-1}{4}\right)\cdot\dfrac{7}{3}+\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\cdot\dfrac{7}{3}\\ =\dfrac{7}{3}\cdot\left(\dfrac{3}{5}+\dfrac{-1}{4}+\dfrac{-3}{4}+\dfrac{2}{5}\right)\\ =\dfrac{7}{3}\cdot\left(1-1\right)\\ =0\\ c)\dfrac{7}{8}:\left(\dfrac{2}{9}-\dfrac{1}{18}\right)+\dfrac{7}{8}:\left(\dfrac{1}{36}-\dfrac{5}{12}\right)\\ =\dfrac{7}{8}:\left(\dfrac{4}{18}-\dfrac{1}{18}\right)+\dfrac{7}{8}:\left(\dfrac{1}{36}-\dfrac{15}{36}\right)\\ =\dfrac{7}{8}:\dfrac{3}{18}+\dfrac{7}{8}:\dfrac{-14}{36}\\ =\dfrac{7}{8}\cdot6+\dfrac{7}{8}\cdot\dfrac{-18}{7}\\ =\dfrac{7}{8}\cdot\left(6-\dfrac{18}{7}\right)\\ =\dfrac{7}{8}\cdot\dfrac{24}{7}\\ =3\)

Bình luận (0)

Các câu hỏi tương tự
GP
Xem chi tiết
H24
Xem chi tiết
PM
Xem chi tiết
LL
Xem chi tiết
LL
Xem chi tiết
LL
Xem chi tiết
LL
Xem chi tiết
HK
Xem chi tiết
LL
Xem chi tiết
H24
Xem chi tiết