Question

a)\(3^{-1}\).\(4^x\)=\(\dfrac{5}{3}.2^7\)

b) \(9^{-x}\).\(27^x\)=243

 

Answer 1

a: =>4^x=640

=>\(x\in\varnothing\)

b: =>\(3^{-2x}\cdot3^{3x}=243\)

=>3^x=243

=>x=5