a: (2x-1)2=25
=>\(\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}2x=6\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
b: \(\left(-3\right)^x+3\cdot5=-12\)
=>\(\left(-3\right)^x=-12-15=-27\)
=>\(\left(-3\right)^x=\left(-3\right)^3\)
=>x=3
a, (2x - 1)2 = 25 = 52
=> 2x - 1 = 5 => 2x = 6 => x = 3
b,(-3)x + 3 . 5 = -12
=> (-3)x + 15 = -12
=> (-3)x = -27
=> (-3)x = (-3)3
=> x = 3