Question

a)203.43-103.43-300

B) 40-40.2018⁰+9¹⁸-9⁰

c) 25.{32:[155-3(16-9)²]} .

Answer 1

\(a,=43\left(203-103\right)-3\cdot100=43\cdot100-3\cdot100\\ =100\left(43-3\right)=100\cdot40=4000\\ b,=40-40\cdot1+9^{18}-1\\ =9^{18}-1\\ c,=25\left[32:\left(155-3\cdot7^2\right)\right]=25\left[32:\left(155-147\right)\right]\\ =25\left(32:8\right)=25\cdot4=100\)

Answer 2

a: \(203\cdot43-103\cdot43-300=43\cdot100-300=4000\)

b: \(40-40\cdot2018^0+9^{18}-9^0\)

\(=40-40+9^{18}-1\)

\(=9^{18}-1\)