Question

a x-2013/8 +x-2004/6+x-2006/5 =10-x-2005/4

Answer 1

(*sửa*)

\(\dfrac{x-2013}{8}+\dfrac{x-2003}{6}+\dfrac{x-2006}{5}=10-\dfrac{x-2005}{4}\\ \Rightarrow\dfrac{x-2013}{8}+\dfrac{x-2003}{6}+\dfrac{x-2006}{5}+\dfrac{x-2005}{4}=10\\ \Rightarrow\left(\dfrac{x-2013}{8}-1\right)+\left(\dfrac{x-2003}{6}-2\right)+\left(\dfrac{x-2006}{5}-3\right)+\left(\dfrac{x-2005}{4}-4\right)=0\\ \Rightarrow\dfrac{x-2021}{8}+\dfrac{x-2021}{6}+\dfrac{x-2021}{5}+\dfrac{x-2021}{4}=0\\ \Rightarrow\left(x-2021\right)\left(\dfrac{1}{8}+\dfrac{1}{6}+\dfrac{1}{5}+\dfrac{1}{4}\right)=0\\ \Rightarrow x-2021=0\\ \Rightarrow x=2021\)