b)\(N=\dfrac{yz}{x^2}+\dfrac{zx}{y^2}+\dfrac{xy}{z^2}\)
\(N=\dfrac{xyz}{x^3}+\dfrac{xyz}{y^3}+\dfrac{xyz}{z^3}\)
\(N=xyz\left(\dfrac{1}{x^3}+\dfrac{1}{y^3}+\dfrac{1}{z^3}\right)\)
Ta cm đẳng thức sau:\(x^3+y^3+z^3=3xyz\Leftrightarrow x+y+z=0\)
ĐT\(\Leftrightarrow x^3+y^3-3xyz=-z^3\)
\(\Leftrightarrow\left(x+y\right)\left(x^2-xy+y^2\right)-3xy=-z^3\)
\(\Leftrightarrow-zx^2+xyz-zy^2-3xyz=-z^3\)
\(\Leftrightarrow x^2+2xy+y^2=z^2\)
\(\Leftrightarrow\left(x+y\right)^2=z^2\)
\(\Leftrightarrow\left(-z\right)^2=z^2\)(luôn đúng)
Áp dụng\(\Rightarrow N=xyz.\dfrac{3}{xyz}=3\)
a, (M-1)/70-71=m
m=(71^9+71^8....71+1)
71m=71^10+...71^2+71
70m=71^10-1
(M-1)/70=71^10+70
M-1=70(71^10+70)
M=70(71^10+70)-1