Để A là số nguyên dương thì \(\left\{{}\begin{matrix}\sqrt{x}⋮\sqrt{x}-3\\\dfrac{\sqrt{x}}{\sqrt{x}-3}>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\sqrt{x}-3+3⋮\sqrt{x}-3\\\sqrt{x}-3>0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\sqrt{x}-3\in\left\{1;-1;3;-3\right\}\\x>9\end{matrix}\right.\Leftrightarrow x\in\left\{14;36\right\}\)