Question

a) \(\dfrac{2x^2-3x-2}{2x+1}\)=3

b)B=\(\dfrac{x-3\sqrt{x}+4}{x-2\sqrt{x}}\)=\(\dfrac{1}{\sqrt{x}-2}\)

Answer 1

b: =>x-3căn x+4=căn x

=>(căn x-2)^2=0

=>căn x-2=0

=>x=4(loại)