\(a.\dfrac{5}{12}+\dfrac{3}{4}-\dfrac{1}{3}=\dfrac{5}{12}+\dfrac{9}{12}-\dfrac{4}{12}=\dfrac{10}{12}=\dfrac{5}{6}\\ b.\dfrac{11}{24}-\dfrac{3}{7}+\dfrac{1}{4}=\dfrac{77-72+42}{168}=\dfrac{47}{168}\)
\(\dfrac{5}{12}+\dfrac{3}{4}-\dfrac{1}{3}=\dfrac{5}{6}\)
\(\dfrac{11}{24}-\dfrac{3}{7}+\dfrac{1}{4}=\dfrac{47}{168}\)